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daimath
Junior Member

USA
6 Posts

 Posted - 03/26/2014 :  05:14:30 In an internet article about the globular cluster known as M22 http://www.ask.com/wiki/Messier_22?o=2802&qsrc=999&ad=doubleDown&an=apn&ap=ask.com it is stated that the distance to the object is 10,600 +/- 1,000 light years and that the object subtends an angle in the sky measuring 39 minutes (i.e. 0.65 degree). It is also stated that the size of the object is 99 +/- 9 light years.Based on what I remember of my high school math I calculate that the size of the object is 120 +/- 11 light years. My calculation is :Minimum size = sin(0.65) x 9,600 = 108.9Median size = sin(0.65) x 10,600 = 120.3Maximum size = sin(0.65) x 11,600 = 131.6Have I mis-remembered my math?

the_hill1962
Advanced Member

USA
1469 Posts

 Posted - 03/26/2014 :  15:26:57 I agree with you. I used the tangent ratio and came up with the same answer. Sorry, I have not checked your work since my answer was the same as yours I figure you set it up correctly (I see you used sine).I have found mistakes on "big" sites also. The most recent was an incorrect statement on wikipedia. I would have written in to correct them but it appeared that you had to register and jump through hoops to make any sort of comments.I hope that you take the time to contact the author of what you found on ask.com

daimath
Junior Member

USA
6 Posts

 Posted - 03/26/2014 :  19:52:13 Thanks for taking the time to reply with your confirmation the_hill1962. It is appreciated.

TchrWill
Advanced Member

USA
80 Posts

 Posted - 04/04/2014 :  12:06:33 [quote]Originally posted by daimathIn an internet article about the globular cluster known as M22 http://www.ask.com/wiki/Messier_22?o=2802&qsrc=999&ad=doubleDown&an=apn&ap=ask.com it is stated that the distance to the object is 10,600 +/- 1,000 light years and that the object subtends an angle in the sky measuring 39 minutes (i.e. 0.65 degree). It is also stated that the size of the object is 99 +/- 9 light years.Based on what I remember of my high school math I calculate that the size of the object is 120 +/- 11 light years. My calculation is :Minimum size = sin(0.65) x 9,600 = 108.9Median size = sin(0.65) x 10,600 = 120.3Maximum size = sin(0.65) x 11,600 = 131.6Based on what I remember of my high school math I calculate that the size of the object is 120 +/- 11 light years. My calculation is :Minimum size = sin(0.65) x 9,600 = 108.9Median size = sin(0.65) x 10,600 = 120.3Maximum size = sin(0.65) x 11,600 = 131.6As the hill1962 pointed out, the tangent ratio is the proper angle function to use as the cluster diameter D is 2R whereD = 2R[D(tan.325)] resulting inMinimum D = 2[9600tan.325] = 108.9097 = 108.91Median D = 2[10600tan.325] = 120.254 = 120.25 = 120 +/-11Maximum D = 2[11600tan.325] = 131.599 = 131.6depending on your choice of rounding off rules. As the hill1962 again points out, big sites often result in big errors. I tried manipulating the numbers around but could not find any path that resulted in a diameter of 99 +/-9. If I find one, I will let you know.

Subhotosh Khan
Advanced Member

USA
9117 Posts

 Posted - 06/29/2014 :  10:08:38 quote:Originally posted by daimathIn an internet article about the globular cluster known as M22 http://www.ask.com/wiki/Messier_22?o=2802&qsrc=999&ad=doubleDown&an=apn&ap=ask.com it is stated that the distance to the object is 10,600 +/- 1,000 light years and that the object subtends an angle in the sky measuring 39 minutes (i.e. 0.65 degree). It is also stated that the size of the object is 99 +/- 9 light years.Based on what I remember of my high school math I calculate that the size of the object is 120 +/- 11 light years. My calculation is :Minimum size = sin(0.65) x 9,600 = 108.9Median size = sin(0.65) x 10,600 = 120.3Maximum size = sin(0.65) x 11,600 = 131.6Have I mis-remembered my math?I read the article - and the angle subtended is 32'(=0.009308 rad.).In that case size indeed is 99 ± 9 lightyears
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