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effort
Senior Member

USA
38 Posts

Posted - 03/02/2014 :  10:04:21  Show Profile
An object traveling in a straight line has position x(t) at time t. If the initial position is x(0) = 2 and velocity of the object is v(t) = (1 + t), what is the position of the object at time t = 3?


I know that the answer is 6.512. I just don't know how to show that. Would you please show me how to solve this?
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Ultraglide
Advanced Member

Canada
299 Posts

Posted - 03/03/2014 :  16:26:08  Show Profile
Are you sure the antiderivative is correct?
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Ultraglide
Advanced Member

Canada
299 Posts

Posted - 03/04/2014 :  23:40:07  Show Profile
Maybe I should rephrase that. Are you sure the velocity function is correct?
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effort
Senior Member

USA
38 Posts

Posted - 03/05/2014 :  13:07:09  Show Profile
Ultraglide, you are right. It was a typo. It should have been
v(t)= (1 + (t)).....only the t should have been squared.

I did figure how to do it. Since the integral of v(t) from 0 to 3= x(3)-x(0)=x(3)- 2 , then 2 + that same integral = x(3) which gives 6.51153
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Ultraglide
Advanced Member

Canada
299 Posts

Posted - 03/06/2014 :  12:13:03  Show Profile
The two velocity functions you wrote are identical. Is there not another 't' in the function, i.e. v(t)=t(1+t)?
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