Author 
Topic 

dauerbach
Average Member
USA
13 Posts 
Posted  08/27/2007 : 20:17:06

My back to school review is in progress, and I am blocking.
For the function f(x) =x^2  4/(x + 3)^2
State the domain: Every real number except 3
Find the x intercept: Totally blocking
Find the y Intercept: +4/9, 4/9
Are the two I did correct? What is the x intercept? 


tkhunny
Advanced Member
USA
1001 Posts 
Posted  08/27/2007 : 22:59:33

yintercept: x = 0 and solve for y. Where does the graph hit the yaxis?
0^2  4/(0+3)^2 = 0  4/3^2 = 4/9
xintercept: y = 0 and solve for x. Where does the graph hit the xaxis?
0 = x^2  4/(x+3)^2 = (x + 2/(x+3))(x  2/(x+3))
Can you find values that work?
Domain: Good. No Range? 


dauerbach
Average Member
USA
13 Posts 
Posted  08/29/2007 : 08:57:28

Honestly, I am not sure. I got 4/9 and it just seemed it should be plus or minus. Obviously not. 


tkhunny
Advanced Member
USA
1001 Posts 
Posted  08/29/2007 : 10:17:23

quote: Originally posted by dauerbach
Honestly, I am not sure. I got 4/9 and it just seemed it should be plus or minus. Obviously not.
It is a common error. consider the following...
x = 4 has only one solution. x = 4
x = 4 has only one solution. x = 4
x = 4 has two solutions. x = 2 and x = 2
How many solutions has:
x = 4 ?
How many solutions has:
x = 4 ? 



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